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Given an array nums containing n + 1 integers where each integer is between 1 and n (inclusive), prove that at least one duplicate number must exist. Assume that there is only one duplicate number, find the duplicate one.
Note:
- You must not modify the array (assume the array is read only).
- You must use only constant, O(1) extra space.
- Your runtime complexity should be less than
O(n2)
. - There is only one duplicate number in the array, but it could be repeated more than once.
class Solution(object):
def findDuplicate(self, nums):
"""
:type nums: List[int]
:rtype: int
"""
left, right = 1, len(nums)-1
while left <= right:
pivot = (left + right) >> 1
cnt = sum(x <= pivot for x in nums)
if pivot < cnt:
right = pivot - 1
else:
left = pivot + 1
return left
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