Given a binary tree, determine if it is a valid binary search tree (BST).
Assume a BST is defined as follows:
- The left subtree of a node contains only nodes with keys less than the node's key.
- The right subtree of a node contains only nodes with keys greater than the node's key.
- Both the left and right subtrees must also be binary search trees.
confused what "{1,#,2,3}"
means? > read more on how binary tree is serialized on OJ.
# Definition for a binary tree node.
# class TreeNode(object):
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None
class Solution(object):
def validate(self, root, minval, maxval):
if root == None:
return True
if minval >= root.val or root.val >= maxval:
return False
return self.validate(root.left, minval, root.val) and self.validate(root.right, root.val, maxval)
def isValidBST(self, root):
"""
:type root: TreeNode
:rtype: bool
"""
if root is None:
return True
return self.validate(root, -sys.maxint-1, sys.maxint)